A wire having mass per unit length of 0.480 g/cm carries a 2.60 A current horizontally to the south.? - lift and carry south india girls
What is the significance and magnitude of the magnetic field minimum necessary to remove this thread straight up?
1 comment:
The magnetic force per unit length = 's weight by thread
Unit length.
F / L = IXB = mg / L
2.6b = 0.00048 kilograms / cm (100 cm / m) (9.8) = 0.47 N / m
B = 0.47/2.6 = 0.181 T East
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